204
edits
No edit summary |
|||
Line 25: | Line 25: | ||
\mathbf{B} = 2\pi\frac{d\Psi_{pol}}{dV}\frac{B^2}{\langle B^2\rangle}\mathbf{e}_\theta + | \mathbf{B} = 2\pi\frac{d\Psi_{pol}}{dV}\frac{B^2}{\langle B^2\rangle}\mathbf{e}_\theta + | ||
2\pi\frac{d\Psi_{tor}}{dV}\frac{B^2}{\langle B^2\rangle}\mathbf{e}_\phi | 2\pi\frac{d\Psi_{tor}}{dV}\frac{B^2}{\langle B^2\rangle}\mathbf{e}_\phi | ||
</math> | |||
so, in Boozer coordinates, | |||
:<math> | |||
B^\theta = 2\pi\frac{d\Psi_{pol}}{dV}\frac{B^2}{\langle B^2\rangle} | |||
\quad | |||
\text{and} | |||
\quad | |||
B^\phi = 2\pi\frac{d\Psi_{tor}}{dV}\frac{B^2}{\langle B^2\rangle} | |||
</math> | </math> | ||
edits