Neutronics in Fusion: Difference between revisions

Created page with "= Nuclear Fusion Reactions = == Deuterium–Tritium (D–T) == <math>^2\mathrm{H} + ^3\mathrm{H} \longrightarrow ^4\mathrm{He} + n</math> Q = 17.6 MeV * Alpha particle: 3.5 MeV * Neutron: 14.1 MeV == Deuterium–Deuterium (D–D) == <math>^2\mathrm{H} + ^2\mathrm{H} \longrightarrow ^3\mathrm{He} + n</math> Q = 3.27 MeV <math>^2\mathrm{H} + ^2\mathrm{H} \longrightarrow ^3\mathrm{H} + p</math> Q = 4.03 MeV == Deuterium–Helium‑3 (D–³He) == <math>^2\math..."
 
Blanked the page
Tag: Blanking
Line 1: Line 1:
= Nuclear Fusion Reactions =


== Deuterium–Tritium (D–T) ==
<math>^2\mathrm{H} + ^3\mathrm{H} \longrightarrow ^4\mathrm{He} + n</math> 
Q = 17.6 MeV 
* Alpha particle: 3.5 MeV 
* Neutron: 14.1 MeV
== Deuterium–Deuterium (D–D) ==
<math>^2\mathrm{H} + ^2\mathrm{H} \longrightarrow ^3\mathrm{He} + n</math> 
Q = 3.27 MeV
<math>^2\mathrm{H} + ^2\mathrm{H} \longrightarrow ^3\mathrm{H} + p</math> 
Q = 4.03 MeV
== Deuterium–Helium‑3 (D–³He) ==
<math>^2\mathrm{H} + ^3\mathrm{He} \longrightarrow ^4\mathrm{He} + p</math> 
Q = 18.3 MeV
== Helium‑3–Helium‑3 (³He–³He) ==
<math>^3\mathrm{He} + ^3\mathrm{He} \longrightarrow ^4\mathrm{He} + 2p</math> 
Q = 12.86 MeV
== Proton–Boron‑11 (p–¹¹B) ==
<math>p + ^{11}\mathrm{B} \longrightarrow 3\,^4\mathrm{He}</math> 
Q = 8.68 MeV
== Tritium–Tritium (T–T) ==
<math>^3\mathrm{H} + ^3\mathrm{H} \longrightarrow ^4\mathrm{He} + 2n</math> 
Q = 11.3 MeV
== Proton–Proton Chain (stellar fusion) ==
<math>4p \longrightarrow ^4\mathrm{He} + 2e^+ + 2\nu_e</math> 
Q = 26.7 MeV
== Carbon–Nitrogen–Oxygen (CNO) Cycle ==
<math>4p + ^{12}\mathrm{C} \longrightarrow ^4\mathrm{He} + ^{12}\mathrm{C} + 2e^+ + 2\nu_e</math> 
Q = 25.0 MeV