Boozer coordinates: Difference between revisions

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It is also useful to know the expression of the following object in Boozer coordinates
It is also useful to know the expression of the following object in Boozer coordinates
:<math>
:<math>
\frac{\nabla V\times\mathbf{B}}{B^2} = -\frac{2\pi I_{pol}^d}{\langle B^2\rangle}\mathbf{e}_\theta + \frac{2\pi I_{tor}}{\langle B^2\rangle}~,\mathbf{e}_\phi
\frac{\nabla V\times\mathbf{B}}{B^2} = -\frac{2\pi I_{pol}^d}{\langle B^2\rangle}\mathbf{e}_\theta + \frac{2\pi I_{tor}}{\langle B^2\rangle}\mathbf{e}_\phi~,
</math>.
</math>.

Revision as of 14:14, 5 November 2010

Boozer coordinates are a set of magnetic coordinates in which the diamagnetic ψ×𝐁 lines are straight besides those of magnetic field 𝐁. The periodic part of the stream function of 𝐁 and the scalar magnetic potential are flux functions (that can be chosen to be zero without loss of generality) in this coordinate system.

Form of the Jacobian for Boozer coordinates

Multiplying the covariant representation of the magnetic field by 𝐁 we get

B2=𝐁χ=Itor2π𝐁θ+Ipold2π𝐁ϕ+𝐁χ~.

Now, using the known form of the contravariant components of the magnetic field for a magnetic coordinate system we get

𝐁χ~=B214π2g(ItorΨpol+IpoldΨtor),

where we note that the term in brackets is a flux function. Taking the flux surface average of this equation we find (ItorΨpol+IpoldΨtor)=4π2B2/(g)1=B2V, so that we have

𝐁χ~=B214π2gB2V,

In Boozer coordinates, the LHS of this equation is zero and therefore we must have

gB=V4π2B2B2

Contravariant representation of the magnetic field in Boozer coordinates

In Boozer coordinates the angular covariant B-field components are flux functions

𝐁=η~ψ+Itor2πθ+Ipold2πϕ.

It then follows that

ψ×𝐁=ψ×(Itor2πθ+Ipold2πϕ),

and then the 'diamagnetic' lines are straight in Boozer coordinates and given by Itorθ+Ipoldϕ=const..

It is also useful to know the expression of the following object in Boozer coordinates

V×𝐁B2=2πIpoldB2𝐞θ+2πItorB2𝐞ϕ,.